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What is the identity for tan theta?
The identity for tan(theta) is sin(theta)/cos(theta).
Can sine theta equals tan theta equals theta be equal for small angels?
Yes. (Theta in radians, and then approximately, not exactly.)
Sec squared theta plus tan squared theta equals to 13 12 and sec raised to 4 theta minus tan raised to 4 theta equals to how much?
It also equals 13 12.
How do you find theta if tan theta equals 1 and 0 is less than or equal to theta which is less than 2pi?
tan(theta) = 1 then theta = tan-1(1) + n*pi where n is an integer = pi/4 + n*pi or pi*(1/4 + n) Within the given range, this gives theta = pi/4 and 5*pi/4
What can the function cotangent theta also be expressed as?
cot theta=tan(90-tetha)
If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
What is the identity for tan theta?
The identity for tan(theta) is sin(theta)/cos(theta).
How can you verify 1 plus tan theta divided by 1 minus tan theta equals cot theta plus 1 divided by cot theta minus 1?
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
If tan Theta equals 2 with Theta in Quadrant 3 find cot Theta?
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
What isTan theta?
Tan theta is a function of the number theta.
How do you simplify sin theta times csc theta divided by tan theta?
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Tan theta plus cot theta equals 2csc2 theta?
Yes, it is.
Sin theta 0 and tan theta 0?
4
What is tan theta minus cot theta?
-2(cot2theta)
How do you simplify tan theta cos theta?
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
How do you get the csc theta given tan theta in quadrant 1?
If tan(theta) = x then sin(theta) = x/(sqrt(x2 + 1) so that csc(theta) = [(sqrt(x2 + 1)]/x = sqrt(1 + 1/x2)
