According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the nth one.
The simplest solution, however is Un = 3n - 4.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
Without further restrictions it can be any of an infinite number of formulae.For example, U{n} = (11n⁴ - 110x³ + 385x² - 518x + 176)/8 which gives the next term as 42.However, if it is an ARITHMETIC SEQUENCE (as I suspect your teacher wants), then the nth term is found:Common difference: (-3) - (-7) = 4→ 0th term is -7 - 4 = -11→ nth term U{n} = 4n - 11
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
If you mean: 15 11 7 3 then the nth term is 19-4n
It is: nth term = 5-4n and so the next term will be -19
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
clearly the given series is an arithmetic progression with a common difference of -11,that is every term is obtained by subtracting 11 from the previous term for any A.P, n-th term is a(n)=a(1)+ (n-1)d where a(1)=first term and d=common difference here a(1)=100, and d= -11 so, a(n)=100+(n-1)x(-11) or, a(n)=111-11n
11
Without further restrictions it can be any of an infinite number of formulae.For example, U{n} = (11n⁴ - 110x³ + 385x² - 518x + 176)/8 which gives the next term as 42.However, if it is an ARITHMETIC SEQUENCE (as I suspect your teacher wants), then the nth term is found:Common difference: (-3) - (-7) = 4→ 0th term is -7 - 4 = -11→ nth term U{n} = 4n - 11
The nth term in this sequence is 4n + 3.
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
If you mean: 15 11 7 3 then the nth term is 19-4n
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is: nth term = 5-4n and so the next term will be -19
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.