Assuming x**2+2x-24:
Factoring:
ax**2 + bx + c
Step 1: Multiply coefficients of first and third terms
a∗c
Step 2: Factor product of coefficient of first and third term (a*c), choose 2
factors whose sum is the coefficient of the second term (b)
a∗c=d∗e
d+e=b
Step 3: Rewrite equation
ax2 + dx + ex + c
Step 4: Factor sets of terms (first and second, third and fourth)
gx(hx + i) + j(hx + i)
where: g is the greatest common factor of a and d
where: j is the greatest common factor of e and c
where: h = a ÷ g, e ÷ j
where: i = d ÷ g, c ÷ j
Step 5: Combine Like terms:
(gx + j)(hx + 1)
Example:
Step 1: Multiply coefficients of first and third terms
1*-24 = -24
Step 2: Factor product of coefficient of first and third term (a*c), choose 2
factors whose sum is the coefficient of the second term (b)
-24=2*2*2*3*-1
-24=
-2*12, 2*-12
-4*6, 4*-6
-3*8, 3*-8
-4+6=2
Step 3: Rewrite equation
x**2-4x+6x-24
Step 4: Factor sets of terms (first and second, third and fourth)
gx(hx + i) + j(hx + i)
where: g is the greatest common factor of a and d
where: j is the greatest common factor of e and c
where: h = a ÷ g, e ÷ j
where: i = d ÷ g, c ÷ j
x(x-4)+6(x-4)
Step 5: Combine Like terms:
(x+6)(x-4)
That's not a trinomial, but it factors to x(x + 19)
x2-7x-44 (x-11)(x+4)
x2 + 18x - 50 does not have rational factors.
(x + 3)(x - 2)
x2+2x-63 = (x-7)(x+9) when factored
-((x + 2)(x - 9))
That factors to (x - 14)(x - 2)
A trinomial.
The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)
x2+14x+49 = (x+7)(x+7) when factored
Yes!
x + 4
x2-18x+81 = (x-9)(x-9) when factored
x2+15x+14 = (x+1)(x+14)
vbh
x2 + 4x - 60 factors into (x + 10)(x - 6). You can use the FOIL method to check your answers when you factor.
-x2 + 2x + 48 = (x +6)(8 - x)