Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.
None of the numbers you listed are evenly divisible by 1000.
Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
Eight is divisible, out of these numbers, by only 2.
1,089 is divisible by these numbers: 1, 3, 9, 11, 33, 99, 121, 363, 1089.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Yes; all numbers that are divisible by 9 are divisible by 3.
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.
The numbers 2, 3, and 9 are all divisible by 1.
A number is divisible by 9 if all the digits add up to 9 or are a factor of. IF the digits add up to 9 (or a factor of 9), they will automatically be a factor of 3.Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.
1350 is divisible by all of the numbers of 3, 6 and 9
No. It is the other way round.
yes because 3 fits in 9 perfectly
yEAH, i THINK SO
Any that are divisible by 9 are also divisible by 3.
They are infinite.