The slope of the line is (diff in y-coord)/(diff in x-coord) = (7-3)/(1+2) = 4/3
So the equation of the line is of the form y = 4/3*x + c where c is a constant to be determined
Equivalently, 3y = 4x + c' where c' is (another) constant to be determined.
The point (1,7) is on this line so 3*7 = 4*1 + c' ie c' = 21-4 = 17
So the equation of the line is 3y = 4x + 17
Points: (-3, 7) and (5, -1) Slope: -1 Equation: y = -x+4
y = 2x + 1.
y=2x+1
y = 3x - 3
using the point slope form: y - y1 = m (x - x1) y - 5 = 3 (x + 1)
Choose the equation of the line that contains the points (1, -1) and (2, -2).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Coordinate: (1, 2) Slope: 4 Equation: y = 4x-2
y=2x+1
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
y = 2x - 1
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
It works out as: y = 3x+8
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
Points: (-3, 7) and (5, -1) Slope: -1 Equation: y = -x+4
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
Equation of the straight line: y = -3/5x+2 in slope intercept form