x3-16xx(x2-16)x(x+4)(x-4)...forgot to finish it, sorry.
The answer is -x3 + x
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
t3-1/27
(x + 2)(3x - 1)(3x + 1)
What about it? Factorise it?
X cubed - X cubed is zero.
x(x - 7)
X3 + 8= (x+2)(x2-2x+4)
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
X2 - 4= (x + 2)(x - 2)===========
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
( x2 - 121 ) = (x + 11) times (x - 11)
x3-16xx(x2-16)x(x+4)(x-4)...forgot to finish it, sorry.
x(x + 3)(x - 4)
6x^3 + 3x = 3x(2x^2 + 1)
It depends on what you wanted to do - graph it, solve it, factorise it, etc.