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sinθ = O/H

cosθ = A/H

tanθ = O/A

cosθ*tanθ = A/H * O/A = AO/AH = O/H

Therefore, sinθ = cosθtanθ = O/H

(Notes: O=opposite, A=adjacent, H=hypotenuse)

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Q: How do you show how sin theta equals cos theta tan theta?
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