It has 0 volume diagonals and 6 face diagonals hence the total number of diagonals are 6
number of diagonals = n(n-3)/2 n - number of sides of the polygon
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
20
There are two diagonals in a trapezoid.
It has 0 volume diagonals and 6 face diagonals hence the total number of diagonals are 6
number of diagonals = n(n-3)/2 n - number of sides of the polygon
The five sided Polygon has 5 diagonals
It has 20 diagonals
0.5*(25-15) = 5 diagonals
14 diagonals
Diagonals in an hexagon: 0.5*(6^2 -3*6) = 9 diagonals
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
A 7 sided polygon has 14 diagonals
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.