5
2
5 first terms in n²+3
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
5, 11, 17, 23, 29
5
it is 8.
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
2
5 first terms in n²+3
5
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5, 11, 17, 23, 29
4,8,12,16,20
5
They are -2, 2, 6, 10 and 14.