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what does it mean when f(x) is differentiable along an interval?

it means that f is continuous along that domain. In other words, the curve f is smooth and does not break at any point along the interval.

what does it mean when f(x) is differentiable at a point c?

It means that f is continuous above the domain given by the interval that is an infinitesimally small distance from c. In other words the curve, f(x), is smooth and does not break along the differentially small interval given by c and at all of the values unimaginably close to c.

what does it mean when the derivative of f(x) at c equals 2?

It means that the instantaneous rate of change (slope) of f(x) at that point is equal to 2.

what does it mean when the derivative of f(x) everywhere along an interval equals 2?

It means that every single point along that interval has the same slope of 2. In other words, that interval yields a line with a slope of 2.

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Q: What does it mean when f is differentiable at x equals 2?
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When was function not having a derivative at a point?

Definition: A function f is differentiable at a if f'(a) exists. it is differentiable on an open interval (a, b) [or (a, &infin;) or (-&infin;, a) or (-&infin;, &infin;)]if it is differentiable at every number in the interval.Example: Where is the function f(x) = |x| differentiable?Answer:1. f is differentiable for any x > 0 and x < 0.2. f is not differentiable at x = 0.That's mean that the curve y = |x| has not a tangent at (0, 0).Thus, both continiuty and differentiability are desirable properties for a function to have. These properties are related.Theorem: If f is differentiable at a, then f is continuous at a.The converse theorem is false, that is, there are functions that are continuous but not differentiable. (As we saw at the example above. f(x) = |x| is contionuous at 0, but is not differentiable at 0).The three ways for f not to be differentiable at aare:a) if the graph of a function f has a "corner" or a "kink" in it,b) a discontinuity,c) a vertical tangent


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Not according to the usual definitions of "differentiable" and "continuous".Suppose that the function f is differentiable at the point x = a.Then f(a) is defined andlimit (h -> 0) [f(a+h) - f(a)]/h exists (has a finite value).If this limit exists, then it follows thatlimit (h -> 0) [f(a+h) - f(a)] exists and equals 0.Hence limit (h -> 0) f(a+h) exists and equals f(a).Therefore f is continuous at x = a.


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A cubic function, continuous, differentiable.


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Definition of Differentiable function?

Let f be a function with domain D in R, the real numbers, and D is an open set in R. Then the derivative of f at the point c is defined as: f'(c) =lim as x-&gt; c of the difference quotient [f(x)-f(c)]/[x-c] If that limit exits, the function is called differentiable at c. If f is differentiable at every point in D then f is called differentiable in D.


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Wherever a function is differentiable, it must also be continuous. The opposite is not true, however. For example, the absolute value function, f(x) =|x|, is not differentiable at x=0 even though it is continuous everywhere.


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Let f(x)=abs(x) , absolute value of x defined on the interval [5,5] f(x)= |x| , -5 &le; x &le; 5 Then, f(x) is continuous on [-5,5], but not differentiable at x=0 (that is not differentiable on (-5,5)). Therefore, the Mean Value Theorem does not hold.


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