If you mean: x+2y = 10 then if y = 3 then x = 4
If you mean: y = 2x and 2y = -x+4 then they are positive and negative straight line equations
Assuming you meant 5x-2y=20... 5x - 2(0) = 20 5x = 20 x = 4 X-intercept is 4
The equation can be simplified to show a value of Y in terms of X. 3X + 2Y +2 = 4Y + 4 3X + 2 = 2Y + 4 3X -2 = 2Y and 2Y = 3X - 2 means that Y = (3/2 X) -1
if x is divisible by 4 then x/4 = y, where y is an integer. so it follows that y = x/(2*2) and therefore 2y = x /2. since y is an integer, so must 2y. since x/2 yields an integer (2y), x must be even.
This means that 2y - 3 = 2y + 4 which is not possible.
x - 2y = 4 Add 2y to both sides: x = 4 + 2y Subtract 4 from both sides: x - 4 = 2y Divide both sides by 2: (x - 4)/2 = y or y = 0.5x - 2
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
The inequality is: x+2y > 4
4
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
x+2y=4. choose random values for x, sub in to get y, and then plot as points in format (x,y) i.e. x=1, 1+2y=4, 2y=3, y=1.5, point 1,1.5 x=2, 2+2y=4, 2y=2, point 2,2. plot both. min of 2 points for a line
x+2y=4. choose random values for x, sub in to get y, and then plot as points in format (x,y) i.e. x=1, 1+2y=4, 2y=3, y=1.5, point 1,1.5 x=2, 2+2y=4, 2y=2, point 2,2. plot both. min of 2 points for a line
2y2-2y-4 = (2y-4)(y+1) when factored
x + 2y - 9 = 4 can be rewritten as x + 2y = 13, but this is as far as you can simplify it because you have two unknowns and one equation.
Put in function form. - 2X + 2Y = 4 2Y = 2X + 4 Y = X + 2 -------------set to 0 X + 2 = 0 X = -2 --------------X intercept
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2