If you layout the sequence...
3, 8, 15, 24, 35... ok so you find the difference between these
3 to 8= +5 8 to 15= +7 15 yo 24= +9 24 to 35= +11
so now you find something called the second difference
which is +2 +2 +2 +2 +2. Then you need to divide the second difference by 2 which is just n^2 as it is a quadratic sequence you are finding.
now you do the nth term which is just 1 2 3 4 5 etc.
and you do your n squared sequence which is 1 4 9 16 25 etc.
and you do your sequence 3 8 15 24 35
you find out that you need from the n squared sequence and your regular sequence which is +2 +4 +6 +8 +10 this is your 2n
add 2n to the divided term n squared and you have your answer,
Answer= n squared +2n ------> (n^2)+2n
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The given sequence is an arithmetic sequence, where the difference between consecutive terms is increasing by 5 each time. The nth term of an arithmetic sequence can be found using the formula: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, n is the term number, and d is the common difference. In this case, the first term ( a_1 = 3 ) and the common difference ( d = 5 ). Therefore, the nth term of this sequence is ( a_n = 3 + (n-1)5 ).
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid.
Based on the simplest polynomial, the answer is T(n) = n^2 + 2n.
The answer would be 120... You are increasing by odd numbers 8, 15 (difference is 7) 24 (difference of 9) 35 (difference of 11) 48 (difference of 13) 63 (difference of 15).... etc.... increasing the terms by odd numbers 7 , 9, 11, 13, 15, 17, 19, 21.. I hope this helps
(n+1)2-1
15(1)
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is 6n+5 and so the next term will be 35