To find the number of terms in the arithmetic sequence given by 1316197073, we first identify the pattern. The sequence appears to consist of single-digit increments: 13, 16, 19, 20, 73. However, this does not follow a consistent arithmetic pattern. If the sequence is intended to be read differently or if there are specific rules governing its formation, please clarify for a more accurate answer.
An arithmetic series is the sequence of partial sums of an arithmetic sequence. That is, if A = {a, a+d, a+2d, ..., a+(n-1)d, ... } then the terms of the arithmetic series, S(n), are the sums of the first n terms and S(n) = n/2*[2a + (n-1)d]. Arithmetic series can never converge.A geometric series is the sequence of partial sums of a geometric sequence. That is, if G = {a, ar, ar^2, ..., ar^(n-1), ... } then the terms of the geometric series, T(n), are the sums of the first n terms and T(n) = a*(1 - r^n)/(1 - r). If |r| < 1 then T(n) tends to 1/(1 - r) as n tends to infinity.
An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is constant. For example, the sequence 2, 5, 8, 11, 14 has a common difference of 3. Another example is 10, 7, 4, 1, which has a common difference of -3. In general, an arithmetic sequence can be expressed as (a_n = a_1 + (n-1)d), where (a_1) is the first term and (d) is the common difference.
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
An arithmetic sequence can be represented using a formula, typically in the form (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (d) is the common difference, and (n) is the term number. Additionally, an arithmetic sequence can be represented as a list of its terms, such as {a1, a2, a3, ..., an}, where each term increases by the common difference (d).
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
49
29
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
6
We need help with answering this question.
An arithmetic series is the sequence of partial sums of an arithmetic sequence. That is, if A = {a, a+d, a+2d, ..., a+(n-1)d, ... } then the terms of the arithmetic series, S(n), are the sums of the first n terms and S(n) = n/2*[2a + (n-1)d]. Arithmetic series can never converge.A geometric series is the sequence of partial sums of a geometric sequence. That is, if G = {a, ar, ar^2, ..., ar^(n-1), ... } then the terms of the geometric series, T(n), are the sums of the first n terms and T(n) = a*(1 - r^n)/(1 - r). If |r| < 1 then T(n) tends to 1/(1 - r) as n tends to infinity.
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.
To find the missing terms in the arithmetic sequence 8, 11, 14, 17, we first identify the common difference. The difference between consecutive terms is 3 (11 - 8 = 3, 14 - 11 = 3, 17 - 14 = 3). Therefore, the terms before 8 can be calculated by subtracting 3: 5 (8 - 3) and 2 (5 - 3). The complete sequence is 2, 5, 8, 11, 14, 17.