answersLogoWhite

0

Again, please clarify the question. Either "x=y^2/cos(x)*pi " or "x=y^2/cos(pi)". From the question it is not possible to tell whether the second "x" is a variable, or a multiplier sign (and if it were a multiplier, you're question is omitting a variable on the cos(x)).

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

SteveSteve
Knowledge is a journey, you know? We'll get there.
Chat with Steve
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa

Add your answer:

Earn +20 pts
Q: What is x y sq over cos x pi?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

What is the derivative of sinπx?

The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)


What is the value of cos pie4?

cos pi over four equals the square root of 2 over 2 This value can be found by looking at a unit circle. Cos indicates it is the x value of the point pi/4 which is (square root 2 over 2, square root 2 over 2)


What is the equation of the line tangent to the curve y equals cos x at the point x equals pi over 6?

y = 2(x) - (pi/3) + (sqrt(3)/2)


Sin x - cos x 0 0?

sin x - cos x = 0sin x = cos x(sin x)^2 = (cos x)^2(sin x)^2 = 1 - (sin x)^22(sin x)^2 = 1(sin x)^2 = 1/2sin x = ± √(1/2)sin x = ± (1/√2)sin x = ± (1/√2)(√2/√2)sin x = ± √2/2x = ± pi/4 (± 45 degrees)Any multiple of 2pi can be added to these values and sine (also cosine) is still ± √2/2. Thus all solutions of sin x - cos x = 0 or sin x = cos x are given byx = ± pi/4 ± 2npi, where n is any integer.By choosing any two integers , such as n = 0, n = 1, n = 2 we can find some solutions of sin x - cos x = 0.n = 0, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(0)(pi) = ± pi/4 ± 0 = ± pi/4n = 1, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(1)(pi) = ± pi/4 ± 2pi = ± 9pi/4n = 2, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(2)(pi) = ± pi/4 ± 4pi = ± 17pi/4


Solve Cos x - 1 equals 0?

cos x - 1 = 0 cos(x) = 1 x = 0 +/- k*pi radians where k = 1,2,3,...