339 + 1 = 340,which is exactly divisible.
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
339 + 1 = 340,which is exactly divisible.
It is 8961 - W*int(8961/W)
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
13533/31 = 436 quotient and 17 remainder 436*31=13516 436*32=13547 13533+14=13547 14 is to be added
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.
20
Oh, dude, let me break it down for you. So, to make 4369 divisible by 6, we need to find the remainder when 4369 is divided by 6. The remainder is 1, which means we need to add 5 to 4369 to make it divisible by 6. Easy peasy, right? Like, who even needs a calculator for that?
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
It is: 36 and so 960/48 = 20