The answer is 41, because if you add 5359+41=5400
and if you divide 5400/75=72
so if we add 41 to 5359 it is surely divisable by 75
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339 + 1 = 340,which is exactly divisible.
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
It is: 36 and so 960/48 = 20
339 + 1 = 340,which is exactly divisible.
It is 8961 - W*int(8961/W)
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
13533/31 = 436 quotient and 17 remainder 436*31=13516 436*32=13547 13533+14=13547 14 is to be added
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.
20
Oh, dude, let me break it down for you. So, to make 4369 divisible by 6, we need to find the remainder when 4369 is divided by 6. The remainder is 1, which means we need to add 5 to 4369 to make it divisible by 6. Easy peasy, right? Like, who even needs a calculator for that?
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
It is: 36 and so 960/48 = 20