The answer is 41, because if you add 5359+41=5400
and if you divide 5400/75=72
so if we add 41 to 5359 it is surely divisable by 75
339 + 1 = 340,which is exactly divisible.
3500/42 give 83 quotient,14 remainder next possibility 42*84 =3528. 28 must be added to 3500 then only it will divisible by 42.now check the dividend 3528 with the following divisor 49,56,63 3528/49=72 divisible 3528/56=63 divisible 3528/63=56 divisible So 3528 is divisible by 42,49,63,56 So 28 must be added 28 is the
Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
339 + 1 = 340,which is exactly divisible.
It is 8961 - W*int(8961/W)
13533/31 = 436 quotient and 17 remainder 436*31=13516 436*32=13547 13533+14=13547 14 is to be added
3500/42 give 83 quotient,14 remainder next possibility 42*84 =3528. 28 must be added to 3500 then only it will divisible by 42.now check the dividend 3528 with the following divisor 49,56,63 3528/49=72 divisible 3528/56=63 divisible 3528/63=56 divisible So 3528 is divisible by 42,49,63,56 So 28 must be added 28 is the
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.
20
Seven
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
It is: 36 and so 960/48 = 20
Well 924 by 48 give 19 as quotient . 48*19 is 912; 48×20 is 960. now 924 + 36 is 960 so 36 is