It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
number of diagonals = n(n-3)/2 n - number of sides of the polygon
The number of triangles formed by the diagonals of a 21 sided polygon is C(21,3) = 21x20x19/3x2x1 = 1,330.
1/2*(n2-3n) = 665 diagonals where n means number of sides
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
No, as long as the polygon is convex.
It is: 0.5*(144-36) = 54 diagonals
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
The five sided Polygon has 5 diagonals
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
A 7 sided polygon has 14 diagonals
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
A polygon with 14 diagonals will have 7 sides
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon