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What is the formula to find sum of n even numbers?
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
What is the Program to find sum of natural number using recursion?
#include #define NUM 100 //since prog is to be written for adding 100 naturalint main(){int i,sum=0;for(i=1;i
Code for sum of first natural numbers in python language?
For the first 5 natural numbers (integers):x = 1 + 2 + 3 + 4 + 5print xFor 'n' amount of natural numbers (Python v2 example)n = int(raw_input('Enter max integer: '))count = 0sumn = 0while count < n:sumn = sumn + 1count = count + 1print sumn
Create a program that will display the sum of all numbers from 1 up to the input number?
to print the sum of first ten numbers:- void main() {int i,sum; sum=0; while(i<=10) sum=sum+i; i=i+1; } printf("The sum is : %d",sum); }
Write a program to find the sum of squares of n natural numbers using c plus plus?
#include#includevoid main(){int sum_sqr(int n);clrscr();printf("%d",sum_sqr(5));//Sum of first 5 natural numbers' square valuesgetch();}int sum_sqr(int n){int i,sum=0;for(i=1;i
The variance of first n natural numbers is?
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
How do you find the mean of first n natural numbers?
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
What is the sum of the first 225 natural numbers?
Formula for sum of first natural number = n(n+1)/2 , here n=225 so, answer is 225(225+1)/2 = 25425
What is the sum of the squares of the first 20 natural numbers 1 to 20?
The sum of the first N square numbers is: N*(N+1)*(2N+1)/6 So putting N = 20 gives 2870.
What is the sum of the numbers from 1 to 100?
Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
What is the c plus plus program for printing sum to n natural numbers?
main() { int i, n, sum=0; cout<<"Enter the limit"; cin>>n; for(i=0;i<=n;i++) sum=sum+i; cout<<"sum of "<<n<<" natural numbers ="<<sum; getch(); }
Find the mean of n natural numbers?
Mean = (sum of the n numbers)/n
How do you get the sum of consecutive cubed numbers?
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Program to calculate the sum of first ten natural numbers?
Algorithm to find the sum of first n natural numbers:1. Read n.2. Initialize N=1.3. Initialize sum S=0.4. Calculate S=S+N.5. Calculate N=N+1.6. If N>n, then goto step 7 else goto step 4.7. Write the sum S.8. Stop.
How do you calculate the sum of all numbers from 1 through 61?
The sum of the first "n" numbers is equal to n(n+1)/2.
What is the minimum unique array sum that can be achieved?
The minimum unique array sum that can be achieved is when all elements in the array are different, resulting in the sum of the array being equal to the sum of the first n natural numbers, which is n(n1)/2.
