We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
There are 23 = 8 possible outcomes.
If each coin is a different color, then there are 32 possible outcomes. If you can't tell the difference between the coins, and you're just counting the number of heads and tails, then there are 6 possible outcomes: 5 heads 4 heads 3 heads 2 heads 1 heads all tails
16
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
There are 23 = 8 possible outcomes.
I believe there would be 11 possible outcomes!
If you toss eight coins, there are 256 (28) different outcomes.
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
9
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
24 possible outcomes.
There are eight (8).