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Q: Find the area of a rhombus whose one side is 13 cm and the altitude is 10 cm?

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Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.

Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter

A = baWhere A = areab = length of the basea = altitude (height).

123

28

30

150 sq meters

Area of the rhombus: 0.5*8*10 = 40 square feet

Area of a rhombus = 0.5 times the product of its diagonals

That is one of the ways of finding the area of a rhombus. The area is half the product of the diagonals. In this case, 1/2 of 7 x 4.4 or .154. You can also find the area of a rhombus by using one side as the base and finding an altitude for that base and multiplying them. There is a third way using trigonometry.

With perimeter 10 and all sides equal fora rhombus, each side (base) is 10/4 = 2.5 inch Area = base times altitude = 2.5 x 12 = 30

Area = 0.5*12*8 = 48 square units

The answer is given below.

first tell me the formula

The height or altitude of triangle: (2*45)/15 = 6cm Check: 0.5*15*6 = 45 square cm

altitude(height)=(Area * 2) /length(Base)

It is double the length of the base, in square units.

ind the area of the rhombus if AE = 20 m and DE = 32 m.

It is: 0.5*10*12 = 60 square m

14*8 = 112 sq cm

Find the area of a rhombs with diagonals that measure 8 and 10.

half of base times altitude.

if those are the measurements then that is not a rhombus, rhombi are 4 sided shapesthat have all equal sides

54

well since we know that the area of a isosceles tapezoid is the height(altitude)times twice the median divided by two, so the answer is 9(2)(12)/2=108