Using x instead of theta, cos2x/cosec2x + cos4x = cos2x*sin2x + cos4x = cos2x*(sin2x + cos2x) = cos2x*1 = cos2x
It also equals 13 12.
It is 1.
Zero. Anything minus itself is zero.
cosine (90- theta) = sine (theta)
- cos theta
sin(theta) = 15/17, cosec(theta) = 17/15 cos(theta) = -8/17, sec(theta) = -17/8 cotan(theta) = -8/15 theta = 2.0608 radians.
Yes. (Theta in radians, and then approximately, not exactly.)
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
theta = arcsin(0.0138) is the principal value.
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Yes, it is.
Theta equals 0 or pi.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
If r-squared = theta then r = Â±sqrt(theta)
Tangent (theta) is defined as sine (theta) divided by cosine (theta). In a right triangle, it is also defined as opposite (Y) divided by adjacent (X).
The answer depends on what theta is and the units of its measurement.
It is a mathematical expression.