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It also equals 13 12.

Q: Sec squared theta plus tan squared theta equals to 13 12 and sec raised to 4 theta minus tan raised to 4 theta equals to how much?

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It is 1.

Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.

Since there is no equation, there is nothing that can be solved.

Zero. Anything minus itself is zero.

1

Related questions

Tan^2

It is 1.

If r-squared = theta then r = Â±sqrt(theta)

Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.

It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.

Cosine squared theta = 1 + Sine squared theta

Since there is no equation, there is nothing that can be solved.

1 - sin2(q) = cos2(q)dividing through by cos2(q),sec2(q) - tan2(q) = 1

Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.

cos2(theta) = 1 so cos(theta) = Â±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0

cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1

Cos theta squared