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What are the two positive integers that have a product of 98 where one integer is twice the other?

The integers are 14 and 7.


The larger of 2 positive integers is 5 more than twice the smaller integer The product of the integers is 52 find the integers?

y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.


One integer is three more than twice another integer If the sum of the two integers is 36 what is the smaller integer?

ok this is what it looks like to me...I definitely could be wrong. one integer is three more than twice another integer if one integer is three more than another number (x+3=y) Then you just multiply "the other number" by 2. (x+3=2*y) Sum of two integers is 36....so add them (x+y=36) Solve that equation for one number so...(y=36-x) Then you would plug that equation into the first equation where there is a y: (x + 3 = 2*(36-x))


The sum of two numbers is 70 The larger number is 4 more than twice the smaller number Whta is the smaller number?

16.5


How would you find 3 consecutive integers such that twice the third is 15 more than the first?

Let's denote the first integer as x. The next two consecutive integers would be x+1 and x+2. According to the given condition, twice the third integer (2(x+2)) is equal to 15 more than the first integer (x+15). Setting up the equation: 2(x+2) = x + 15. Solving this equation will give you the first integer, which you can then use to find the consecutive integers.

Related Questions

The larger of two integer is twice the smaller when the recipical of the smaller integer is subtracted from the larger the result is the recipical of the smaller integer?

Let L equal the larger of the two integers and S the smaller. Then L=2S. Also L-1/S=1/S. Starting with this second equation and solving for L results in L=2/S. Equating the two values of L produces 2/S=2S and 1/S=S. The solutions to this last equation are S=1 or S=-1. If L is to be the larger of the two integers, then S must equal 1 and L must equal 2.


Find two consecutive integers such that the larger is nine more than twice the smaller?

-10 and -11.


Find two consecutive odd integers if twice the larger increased by the smaller equals 85?

27, 29


If sum of the smaller of two consecutive integers and twice the larger integer is A what are the integers?

Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3


What is the integers that have seven more than another integer Twice the larger integer is one less than the square of the smaller integer find the 2 integer?

a = b + 7; 2a = b2 - 1. Substituting: 2b + 14 = b2 - 1 or b2 - 2b - 15 = 0 Factors are (x - 5)(x + 3) b = 5, a = 12. Also works with b = -3 and a = 4


What are the two positive integers that have a product of 98 where one integer is twice the other?

The integers are 14 and 7.


The sum of an integer and twice the next consecutive integer is 29. What are the integers?

9 and 10 9 + 2(10) = 29


Two positive integers have a product of 98 one integer is twice the other?

The two integers are 7 and 14. 7 x 14 = 98.


The larger of 2 positive integers is 5 more than twice the smaller integer The product of the integers is 52 find the integers?

y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.


How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?

They are 14, 16 and 18.


One integer is 3 more than twice another integer if the sum of the two integers is 36 what is the smaller integer?

let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.


How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?

The numbers are 14, 16 and 18.