no one wants to know the answer. its freaking math
The integers are 14 and 7.
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
ok this is what it looks like to me...I definitely could be wrong. one integer is three more than twice another integer if one integer is three more than another number (x+3=y) Then you just multiply "the other number" by 2. (x+3=2*y) Sum of two integers is 36....so add them (x+y=36) Solve that equation for one number so...(y=36-x) Then you would plug that equation into the first equation where there is a y: (x + 3 = 2*(36-x))
16.5
Let the smallest of the three consecutive integers be 'x'. Then the three numbers can be represented by x, (x + 1) and (x + 2) Then, 2(x + 2) - 15 = x (twice the third is 15 more that the first) 2x + 4 - 15 = x 2x - x = 15 - 4 x = 11 The three numbers are thus : 11, 12, and 13. And, 2 x 13 = 26 is 15 more than the first number 11.
Let L equal the larger of the two integers and S the smaller. Then L=2S. Also L-1/S=1/S. Starting with this second equation and solving for L results in L=2/S. Equating the two values of L produces 2/S=2S and 1/S=S. The solutions to this last equation are S=1 or S=-1. If L is to be the larger of the two integers, then S must equal 1 and L must equal 2.
-10 and -11.
27, 29
Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3
The integer 50 is greater than 25. This is because 50 is twice the value of 25, making it the larger number. Thus, when comparing these two integers, 50 is the greater one.
a = b + 7; 2a = b2 - 1. Substituting: 2b + 14 = b2 - 1 or b2 - 2b - 15 = 0 Factors are (x - 5)(x + 3) b = 5, a = 12. Also works with b = -3 and a = 4
The integers are 14 and 7.
9 and 10 9 + 2(10) = 29
The two integers are 7 and 14. 7 x 14 = 98.
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.
They are 14, 16 and 18.