Choose the equation of the line that contains the points (1, -1) and (2, -2).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
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x = 1 (the line intersects the x-axis at 1, and is parallel to the y-axis)We cannot write the equation on the Slope-intercept form, since the slope of the line is undefined. 1 is the x-coordinate of any point on the given line.
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
y=2x+1
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
It works out as: y = 3x+8
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
y = 2x - 1
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
Point: (2, -1) Slope: -5 Equation: y = -5x+9
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
y = 2x + 1.