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Assuming that the measurements refer to a rectangle, the diagonal would be

sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)

Q: What is the diagonal measurement of 27 ft by 12 ft?

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By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft

Divide by '12' 27/12 = 2 ft 3 inches or 2.25 ft.

Using Pythagoras Theorem then the diagonal = √(242 + 242) = √1152 = 33.94 ft (2dp)

Sqrt(282 + 402) = a whisker under 48 ft 10 in

Approximately 17 feet.

Related questions

The diagonal of a rectangle 8 feet by 12 feet is âˆš208 feet, or about 14 feet 5.06 inches.

The diagonal measurement of an 8 ft square is: 11.31 feet.

14 ft

I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.

The diagonal is ~16.97 feet.

Don't tell me you are in class!

About 8.5 feet.

By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft

Around 17.8. I did this with cossin, but check the answer with a calculator

36.8782 ft

(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)

46.648 ft