The 'n'th term is [ 13 + 5n ].
58
It is: 5n+3 and so the next term is 28
The nth term is 3(n+1). The twenty-third term is equal to 3 x (23 + 1) = 72
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
A simple answer, based on a linear rule is U(n) = 5n - 23 for n = 1, 2, 3, ...
58
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
All you have to do is add 5 each time(x+5) It's 43
It is: 27-2n
It is T(n) = n2 + 4*n + 2.
Un = 5n - 2
tn = n2 - n + 3It is 75359152333455975
5, 11, 17, 23, 29
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
It is: 5n+3 and so the next term is 28
We note that the numbers rise by addition of ;7;7 between terms. Hence we can write 7n . The first term( n- 1) is '9' So we can write 7(1) + c = 9 7 + c = 9 c = 2 So the nth term becomes 7n + 2