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The sum of three consecutive odd integers is 5 less than twice the smallest of these integers?
Let the inegers be x+1, x+3, and x+5, these are 3 consecutive odds, we could have used x and x+1 and x+3, if x was odd Now the next part is often confusing. So let's say the sum was S, we have S=2(x+1)-5. Now, S= 3x+9 So we have 3x+9=2x+2-5 or x=-9-5+2 so x=-12 x+1=-11 which is odd x+3=-9 x+5=-7 The sum is -27 -27=2(-11)-5 So to see for usre if this works.. our sum is -27 and that is 5 less than twice -11 which is -22. That is to say -27 is 5 less than -22. Would this work with the positive integers 7, 9, and 11? The sum is 27 and the smallest is 7, but 27 does not equal 14-5, so no.
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Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?
This equation works out to 2x = x + 11. This is because the three consecutive odd integers can be represented by x, x + 2, and x + 4. From the equation 2x - x = 11, so x = 11. Checking, 2 times 11 = 22 which is 7 more than 15. The three integers are 11, 13 and 15.
Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91?
98
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
How do you find three consecutive integers so that twice the first increased by three times the third will be -24?
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
The sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest and greatest integers?
three consecutives numbers: a = smallest a+2 a+4 14 less = -14 than twice the smallest = 2a so... a+a+2+a+4=-14+2a 3a+6=-14+2a 3a-2a=-14-6 a=-20 answer: smallest = -20 greatest = -16
What are 3 consecutive integers such that twice the smallest is 12 more than the largest?
-- Call the three consecutive integers (x-1), x, and (x+1).-- Twice the smallest is 2(x-1) or (2x-2).-- 12 more than the largest is (x+1)+12 or (x+13).-- These are equal, so2x - 2 = x + 13Subtract 'x' from each side of the equation:x - 2 = 13Add 2 to each side:x = 15 .-- The smallest of the three numbers is (x-1) = 14.-- The three consecutive integers are 14, 15, and 16.-- Twice the smallest is 28.-- 28 is 12 more than 16.QED, man, QED !
Twice the smallest of three consecutive integers is five more than the largestfind the integers?
7, 8, 9 Let x be the smallest of the three integers; thus, the integers are x, x+1, x+2. From the problem, we get: 2x=(x+2)+5=x+7 2x-x=7 x=7
Find 3 consecutive integers such that twice the smallest is 12 more than the largest?
They are (14, 15, 16).
If sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest integer?
Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.
Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?
This equation works out to 2x = x + 11. This is because the three consecutive odd integers can be represented by x, x + 2, and x + 4. From the equation 2x - x = 11, so x = 11. Checking, 2 times 11 = 22 which is 7 more than 15. The three integers are 11, 13 and 15.
Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91?
98
Whats the answer to Find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third?
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
The sum of three consecutive integers is 13 greater than twice the smallest of the three integersfind the integer?
Integers are n, n + 1 and n + 2, so 3n + 3 = 13 + 2n Subtract 2n from each side: n + 3 = 13 Subtract 3 from each side: n = 10 Job done.
