There are infinitely many polynomials of order 6 (or higher) that will give these as the first six numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
In this particular case, the simplest solution isU(n) = 3*n^2 - 1 for n = 1, 2, 3, ...
To find the nth term of a sequence, we first need to determine the pattern or rule governing the sequence. Looking at the given sequence, we can see that the differences between consecutive terms are increasing by 9, 15, 21, 27, and so on. This suggests that the nth term may involve a quadratic equation. By calculating the second differences, we find that they are constant at 6. Therefore, the nth term for this sequence is given by the formula n^2 + 1.
It is: nth term = 7n-9
To find the nth term in a quadratic sequence, we first need to determine the pattern. In this case, the difference between consecutive terms is increasing by 3, 5, 7, 9, and so on. This indicates a quadratic sequence. To find the 9th term, we need to use the formula for the nth term of a quadratic sequence, which is given by: Tn = an^2 + bn + c. By plugging in n=9 and solving for the 9th term, we can find that the 9th term in this quadratic sequence is 74.
foot
Well, darling, the first 5 terms in that fancy sequence are 28, 26, 24, 22, and 20. You get those numbers by plugging in n values 1 through 5 into the formula 30-2n. So, there you have it, sweet cheeks!
(13 + 15 + 26 + 11 + 26 + 16 + 12)/7 = 17 ====
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = 7n-9
It is: nth term = 35-9n
46n9
It is: 26-8n
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
[ 6n + 8 ] is.
It is: 26-6n
Tn = 10 + n2
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
t(n) = 4n2 - 4n + 2