What is the nth term for 2 11 26 47 74 107?

Answer 1

There are infinitely many polynomials of order 6 (or higher) that will give these as the first six numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
In this particular case, the simplest solution isU(n) = 3*n^2 - 1 for n = 1, 2, 3, ...

Answer 2

Well, honey, the pattern here seems to be increasing by 9, 15, 21, 27, and 33. So, if we continue this trend, the nth term formula for this sequence would be n^2 + 7. But hey, don't take my word for it, go ahead and plug in some numbers to double-check.

Answer 3

To find the nth term of a sequence, we first need to determine the pattern or rule governing the sequence. Looking at the given sequence, we can see that the differences between consecutive terms are increasing by 9, 15, 21, 27, and so on. This suggests that the nth term may involve a quadratic equation. By calculating the second differences, we find that they are constant at 6. Therefore, the nth term for this sequence is given by the formula n^2 + 1.

Answer 4

Oh, dude, chill out. The nth term for this sequence is n^3 + 1. So, like, if you plug in n=1, you get 2, n=2 gives you 11, and so on. It's just a simple cubic function with a little twist.

Answer 5

134

Answer 6

jj

Answer 7

10