0
If the line falls on the point 18 17 and 8 8 what is the slope?
Wiki User
∙ 13y ago
m=y2-y1/x2-x1
m=17-8/18-8
m=9/10
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What is the slope of a line whose equation is 17x-12y equals -36?
17/12
What is the straight line equation that has a slope of 1 over 3 and passing through a point of 2 and minus 5 on the line?
y = mx+c where m is the slope and c is the intercept on the y axis So: 1/3*2+c = -5 c = -5-2/3 c = -17/3 Therefore: y = 1/3x-17/3 => 3y = x-17 which can be expressed as x-3y-17 = 0
Find the slope of the line through the points -13 and 17?
There is not enough information to answer this question. As currently written, a geometric point with only one variable is operating only on the x-axis (one dimensional). Asking the slope between two points that only exist on the x-axis is automatically zero. Slope is normally calculated using points on a two-dimesional grid with each point being represented by (x,y). To calculate the slope in this case you take the change in y divided by the change in x. Example: Find the slope of the line through the points (-13,4) and (17,14). Slope = Change in Y/Change in X = (-13-17)/(4-14) = -30/-10 = 3
What is the equation of the line that passes through the points (12 8) and (17 16)?
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?
Circle equation: x^2 -4x +y^2 -6y = 4 Completing the squares: (x-2)^2 +(y-3)^2 = 17 Point of contact: (6, 4) Center of circle: (2, 3) Slope of radius: 1/4 Slope of tangent line: -4 Tangent equation: y-4 = -4(x-6) => y = -4x+28 Tangent line equation in its general form: 4x+y-28 = 0
What is the equation of a line through the point (2 17) and has a slope of 7?
write an equation that has a slope 7 and passes through the point (2,17)
What is slope of line passing through points 4-13?
17
What is the slope of the line described by the equation y - 5 -3(x - 17)?
If you mean: y - 5 = -3(x - 17) then:The slope is -3 and the line passes through the point (17, 5).It can be rearranged into y = -3x + 56 to also give the slope of -3 and the y-intercept of 56
What is the slope of the line that is perpendicular to y -2x 17?
If you mean: y = -2x+17 then the perpendicular slope line is 1/2 or 0.5
Find th slope if it exists of the line containing the pair of points -5-13 and -17-19?
First we note that the slope does exist between the two points because the two points do not have the same x co-ordinate. Next, we apply the slope formula. slope=(y2-y1)/(x2-x1) Note that it does not matter which point you call as 1 or 2, you will still get the same result. For this example we will call point (-5,-13) as point 1 and (-17,-19) as point 2. Therefore: slope=(-19-(-13)) / (-17-(-5)) = (-6) / (-12) = 1/2 Therefore, the slope of the line containing the points (-5,-13) and (-17,-19) is 1/2.
Find the point on the line y equals 4x plus 7 that is closest to the origin?
(28/17,7/17) The point on the line closest to the origin is the point on a line through the origin that is perpendicular to the given line. Because the slope of the perpendicular is the negative reciprocal of the given line, it has a slope of -1/4 and is given by the equation: y=(-1/4)x The x-coordinate of the point of intersection is found by solving the following: (-1/4)x=4x+7 -x=16x+28 -17x=28 x=-28/17 y=(-1/4)(-28/17)=7/17
What is the slope of the line that passes through the pair of points 17 and 101?
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
What is the slope of the line parallel to -3x 5y 17?
It will have the same slope but a different y intercept
Write the equation in slope intercept form of the line that has a slope of -3 and contains the point 4 5?
y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form
What is the slope of the line that passes through the points (-12 -17) and (21 5)?
Points: (-12, -17) and (21, 5) Slope: 2/3
What is the slope intercept form of the equation of the line that is perpendicular to 7x - 8y equals 12 and contains the point P at -3 1?
The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m A line with slope m' through point (X, Y) has equation: y - Y = m'(x - X) → The line perpendicular to 7x - 8y = 12 through p (-3, 1) is found: 7x - 8y = 12 → 8y = 7x - 12 → y = (7/8)x - 3/2 → The slope of 7x - 8y = 12 is m = 7/8 → The slope of the perpendicular line is m' = -1/m = -1/(7/8) = -8/7 → The line through P with this slope m' is: y - 1 = -8/7(x - -3) → y = (-8/7)x - 24/7 + 1 → y = (-8/7)x - 17/7 This can be rearranged into: y = (-8/7)x - 17/7 → 7y = -8x - 17 → 7y + 8x + 17 = 0
What is the slope of the line y-18x 17?
If you mean: y = -18x+17 then the slope is -18 and the y intercept is 17
