t(3) = 10 - 32 = 1
1 4 9 is a series of squared numbers. The nth term is [ n squared ]
t(n) = t(n - 1) + (10n - 9)
f = 10n + (n - 1)^2 For n=10 f = 10(10) + (10 - 1)^2 f = 181
It is not possible to determine an nth term from a single number.
Nth term With the nth term you substitute the n for the term number (e.g. 50) so the 50th term in 2n+3 would be 2x50+3=103
2500, 100n2Restate the question: what are the 5th and nth term of (10n)2?If this is not your question, please clarify and resubmit the question.Assuming the first term is when n=1, then the 5th term is (10x5)2 = (50)2 =2500.The nth term would be just (10n)2, although you could expand and simplify to get (102)(n2) = 100n2.
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
If you meant: 2 12 22 32 then the nth term = 10n-8
1 4 9 is a series of squared numbers. The nth term is [ n squared ]
It is: 10n-7 and so the next term is 43
15(1)
nth term is n squared plus three
t(n) = t(n - 1) + (10n - 9)
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
10n + 1
16