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If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
11
-4
Coordinate: (1, 2) Slope: 4 Equation: y = 4x-2
As the second line is parallel to the first then the slopes of both lines are the same. 4x + y - 1 = 0 : y = -4x + 1 : Therefore the slope is -4. Using the standard slope-intercept equation of y = mx + c for the second line gives :- 2 = -4x1 + c : 2 = -4 + c : c = 2 + 4 = 6. Therefore the equation of the second line is y = -4x + 6. (Or y + 4x - 6 = 0)
Slope = 4
If you mean: y = 4x+5 then the perpendicular slope is -1/4
If you mean y = 4x-1 then the slope is 4 and the y intercept is -1
The straight line equation is: y = -4x+1
I assume you mean y = 4x If so, then it is 4.
The slope is -4
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.
3
5
y=4x -7
It is: y = -4x+2