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-3x2 plus 10x - 8?
(-3x + 4)(x - 2)
What is the factorization of 3x2 plus 10x plus 3?
3x2 + 10x + 3 = (x + 3)(3x + 1).
How do you solve 3x squared plus 10x- 8 equals 0?
3x2 + 10x - 8 = 0 3x2 + 12x - 2x - 8 = 0 3x(x + 4) - 2(x + 4) = 0 (3x - 2)(x + 4) = 0 So 3x - 2 = 0 or x + 4 = 0 so x = 2/3 or x = -4
How do you factor 3x squared plus 10x minus 8?
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
Factor -3x2 plus 10x - 8?
86 because you times -3 and 2 then you get -6. Then you times 10 and -8 and you get 80. Last thing is to add -6 and 80. You get 86.For the person that answered with that, this is factoring! As in algebra!-3x2+10x-8 -3*-8=24 6*4=24 6+4=10-3x2+6x+4x-8[3xx 2*3x] [2*2x 2*2*2]-3x(x-2)+4(x-2)(x-2)(-3x+4)Answer: (x-2)(-3x+4) not 86...simple mistake, whoever answered that simply thought it was arithmetic -3*2+10*-8.
