""Inasmuch as many have taken in hand to set in order a narrative of those things which have been fulfilled among us, just as those who from the beginning were eyewitnesses and ministers of the word delivered them to us, it seemed good to me also, having had perfect understanding of all things from the very first, to write to you an orderly account, most excellent Theophilus, that you may know the certainty of those things in which you were instructed.""
The answer depends on what theta is and the units of its measurement.
If sin2(theta) = 0, then theta is N pi, N being any integer
tan theta = sqrt(2)/2 = 1/sqrt(2).
The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant
Yes. (Theta in radians, and then approximately, not exactly.)
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
The answer depends on what theta is and the units of its measurement.
0.75
cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
If r-squared = theta then r = ±sqrt(theta)
If tan theta equals 2, then the sides of the triangle could be -2, -1, and square root of 5 (I used the Pythagorean Theorem to get this). From this, sec theta is negative square root of 5. It is negative because theta is in the third quadrant, where cosine, secant, sine, and cosecant are all negative.
If sin2(theta) = 0, then theta is N pi, N being any integer
It is -sqrt(1 + cot^2 theta)
tan theta = sqrt(2)/2 = 1/sqrt(2).
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0