The identity for tan(theta) is sin(theta)/cos(theta).
tan (theta x theta) : must square the value of the angle, theta, before applying the trig function, tangent.
Yes. (Theta in radians, and then approximately, not exactly.)
It also equals 13 12.
tan(theta) = 1 then theta = tan-1(1) + n*pi where n is an integer = pi/4 + n*pi or pi*(1/4 + n) Within the given range, this gives theta = pi/4 and 5*pi/4
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
0.75
The identity for tan(theta) is sin(theta)/cos(theta).
tan (theta x theta) : must square the value of the angle, theta, before applying the trig function, tangent.
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
Tan^2
Tan theta is a function of the number theta.
Yes, it is.
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
4
-2(cot2theta)