Points: (-6, 1) and (2, 3)
Slope or gradient: (3 -1)/(2 - -6) = 2/8 = 1/4
Equation: y -1 = 1/4(x - -6) => y = 1/4x+5/2
y=2x+1
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
Equation of the straight line: y = -3/5x+2 in slope intercept form
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
Choose the equation of the line that contains the points (1, -1) and (2, -2).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Coordinate: (1, 2) Slope: 4 Equation: y = 4x-2
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
y=2x+1
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
It is: y-5 = 2(x-1) => y = 2x+3
y = 2x - 1
x = -2
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
Equation of the straight line: y = -3/5x+2 in slope intercept form