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Q: Write an equation of the line that is perpendicular to the line Y 2x-11 and passes through the point 0 -7?

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Yes, I could, if I knew the slope of the line given.

Coordinate geometry

Y=2x+6

"Y = any number" is perpendicular to "x = -3".

(0,-6) m=-2

Related questions

If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9

Yes, I could, if I knew the slope of the line given.

As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x

Write the equation of the line that passes through the points (3, -5) and (-4, -5)

The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.

sda

Coordinate geometry

Y=2x+6

Slope-intercept form

write a perpendicular 8 and u will get your answer