For the given sequence the simplest formula for the nth term is:
U{n} = n² + 3n - 2
However, that will only work if the sequence continues 68, 86, 106, 128, 152, ... (the difference between successive terms being the difference between the previous 2 terms plus 2).
If the sequence continues differently, then a different polynomial formula with higher powers will be required.
2 + ((6 + 2 * (n - 1) * (n - 1))
[ 6n + 8 ] is.
Each number is increasing by increments of 8 10 12 14 ... etc and so the next number will be 52+16 = 68
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The nth term of the sequence is (n + 1)2 + 2.
2 + ((6 + 2 * (n - 1) * (n - 1))
[ 6n + 8 ] is.
Each number is increasing by increments of 8 10 12 14 ... etc and so the next number will be 52+16 = 68
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term of the sequence is (n + 1)2 + 2.
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
n2 + 3n - 2
58
If the term number is n, then the nth term is 10(n-1) +8.