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It is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question followed by any chosen number in nth position. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution, based on a polynomial of order 2, is
T(n) = n^2 - 1 for n = 1, 2, 3, ...
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What is the nth term for 8 15 24 35 48?
The answer would be 120... You are increasing by odd numbers 8, 15 (difference is 7) 24 (difference of 9) 35 (difference of 11) 48 (difference of 13) 63 (difference of 15).... etc.... increasing the terms by odd numbers 7 , 9, 11, 13, 15, 17, 19, 21.. I hope this helps
What is the nth term for 3 8 15 24 35?
(n+1)2-1
What is the nth term of the sequence 15 25 35 45 55?
15(1)
What is the nth term for 5 11 17 23 29?
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
What is the nth term 11 17 23 29?
It is 6n+5 and so the next term will be 35
