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It is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question followed by any chosen number in nth position. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution, based on a polynomial of order 2, is
T(n) = n^2 - 1 for n = 1, 2, 3, ...
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What is the nth term for 8 15 24 35 48?
The answer would be 120... You are increasing by odd numbers 8, 15 (difference is 7) 24 (difference of 9) 35 (difference of 11) 48 (difference of 13) 63 (difference of 15).... etc.... increasing the terms by odd numbers 7 , 9, 11, 13, 15, 17, 19, 21.. I hope this helps
What is the nth term for 3 8 15 24 35?
(n+1)2-1
What is the nth term of the sequence 15 25 35 45 55?
15(1)
What is the nth term for 5 11 17 23 29?
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
What is the nth term 11 17 23 29?
It is 6n+5 and so the next term will be 35
What is the nth term for 3 8 15 24 35?
(n+1)2-1
What is the formula for the nth term of this sequence 26 17 8 -1?
It is: nth term = 35-9n
What is the nth term for 8 15 24 35 48?
The answer would be 120... You are increasing by odd numbers 8, 15 (difference is 7) 24 (difference of 9) 35 (difference of 11) 48 (difference of 13) 63 (difference of 15).... etc.... increasing the terms by odd numbers 7 , 9, 11, 13, 15, 17, 19, 21.. I hope this helps
What is the nth term of the sequence 15 25 35 45 55?
15(1)
What is the nth term for 5 11 17 23 29?
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
How do you find the nth term?
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
What is the nth term 11 17 23 29?
It is 6n+5 and so the next term will be 35
nth term of 7.14.21.28.35?
The given sequence (7, 14, 21, 28, 35,....) is an arithmetic sequence where each term increases by 7. The nth term of the given sequence is 7n
What is the nth term of 5 13 23 35 49 65?
t(n) = n2 + 5n - 1
Find nth term for sequence 0 5 10 15 20 25 30 35?
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
What is the nth term of 3 8 15 24 and 35?
If you layout the sequence... 3, 8, 15, 24, 35... ok so you find the difference between these 3 to 8= +5 8 to 15= +7 15 yo 24= +9 24 to 35= +11 so now you find something called the second difference which is +2 +2 +2 +2 +2. Then you need to divide the second difference by 2 which is just n^2 as it is a quadratic sequence you are finding. now you do the nth term which is just 1 2 3 4 5 etc. and you do your n squared sequence which is 1 4 9 16 25 etc. and you do your sequence 3 8 15 24 35 you find out that you need from the n squared sequence and your regular sequence which is +2 +4 +6 +8 +10 this is your 2n add 2n to the divided term n squared and you have your answer, Answer= n squared +2n ------> (n^2)+2n
What is the first 5 terms in a sequence when given the nth term n 7?
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
