There are infinitely many possible answers because there are infinitely many polynomials of order 6 (or higher) that will give these as the first six numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution, however, is possibly the following:
U(n) = x^2 + 3*x - 2 for n = 1 ,2, 3, ...
Chat with our AI personalities
2 + ((6 + 2 * (n - 1) * (n - 1))
[ 6n + 8 ] is.
Each number is increasing by increments of 8 10 12 14 ... etc and so the next number will be 52+16 = 68
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The nth term of the sequence is (n + 1)2 + 2.
2 + ((6 + 2 * (n - 1) * (n - 1))
[ 6n + 8 ] is.
Each number is increasing by increments of 8 10 12 14 ... etc and so the next number will be 52+16 = 68
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term of the sequence is (n + 1)2 + 2.
We note that there are a difference of '9' between terms . Hence '9n' Next find the constant 'c' 1st term ; 9(1) + c = 20 => c = 11 2 nd term ; 9(2) + c = 29 => c = 11 nth term is 9n + 11 e.g. 7th term is 9(7) + 11 = 63 + 11 = 74
n2 + 3n - 2
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58