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The vertex of this parabola is at 3 -2 When the x value is 4 the y value is 3 What is the coefficient of the squared expression in the parabolas equation?
Vertex = (3, - 2)Put in vertex form.(X - 3)2 + 2X2 - 6X + 9 + 2 = 0X2 - 6X + 11 = 0=============The coefficeint of the squared term is 1. My TI-84 confirms the (4, 3) intercept of the parabola and the 11 Y intercept shown by the function.
Using the discriminant how many times does the graph of this equation cross the x axis 3x2 plus 6x plus 20?
In this case, the discriminant is less than zero and the graph of this parabola lies above the x-axis. It never crosses.
What is the relationship between a function and its derivative?
The derivative if a function is basically it's slope, or its rate of change. An example is the function y = 4x - 6. This is a line with a slope of 4. The derivative is y' = 4. Another example is the function y = 3x2. This is a parabola with a vertex at (0,0). Its derivative is y' = 6x. At x = 0, the slope of the parabola is 6*0, which is 0, since this is the vertex of the parabola. To the left, at x is -4 for example, the derivative (and therefore slope) is negative. To the right, at x = 5 for example, the derivative is positive. The farther away from the vertex, the greater the value of the derivative so the the slope of the function increases as you move away from the vertex (it gets steeper).
What is the vertex form of the equation y equals x squared plus 6x plus 2?
Y = X2 + 6X + 2set to 0X2 + 6X + 2 = 0X2 + 6X = - 2now, halve the linear coefficient ( 6 ), square it and add it to both sidesX2 + 6X + 9 = - 2 + 9gather terms on the right and factor the left(X + 3)2 = 7(X + 3)2 - 7 = 0==============vertex form(- 3, - 7)=======vertex
What is One factor of 3x2- 6x plus 9?
3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms
What is the x-coordinate of the of the vertex of y equals -3x2 plus 12x-5?
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
The vertex of this parabola is at 3 -2 When the x value is 4 the y value is 3 What is the coefficient of the squared expression in the parabolas equation?
Vertex = (3, - 2)Put in vertex form.(X - 3)2 + 2X2 - 6X + 9 + 2 = 0X2 - 6X + 11 = 0=============The coefficeint of the squared term is 1. My TI-84 confirms the (4, 3) intercept of the parabola and the 11 Y intercept shown by the function.
How do you write the equation for each hyperbola in standard form when the equation is y2-3x2 plus 6x plus 6y equals 18?
y2-3x2+6x+6y= 18 is in standard form. The vertex form would be (y+3)2/24 - (x-1)2/8 = 1
How would you find the vertex of the parabola 1 plus 12x -6x squared?
Parabola: 1+12x-6x^2 Factorizing: -6(x^2 -2x -1/6) Completing the square: -6((x-1)^2 -1 -1/6) => -6(x-1)^2 +7 Vertex of parabola is at: (1, 7)
What is the value of x in the equation y 3x2 6x - 12?
The value of x is 2
What is the answer to this equation 3x2 plus 6x plus 24 equals 0?
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
Using the discriminant how many times does the graph of this equation cross the x axis 3x2 plus 6x plus 20?
In this case, the discriminant is less than zero and the graph of this parabola lies above the x-axis. It never crosses.
What is the vertex form of y -4x2-6x?
The question does not contain an equation: only an expression. An expression cannot have a vertex form.
What is the coordinate for the vertex of the parabola represented by the equation y equals xsquared -6x subtract 16?
-22
What is the line of symmetry for the parabola whose equation is y equals 3x2 plus 24x - 1?
y = 3x^(2) + 24x - 1 Differentiate and equate to '0' dy/dx = 6x - 24 = 0 6x - 24 = 0 6x = 24 x = 4 is the line of symmetry.
