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nth term = n*(n+2)+(n-2) when

1st term = 2; 2nd term = 8; 3rd term = 16; 4th term = 26; 5th term = 38; 6th term = 52

Step 1: look at n=3 and 4 and try to come up with a formula that is close

Step 2: first try multiplication for n=3 which should be 16 which is close to 3x5; for n=4 it should be 26 which is close to 4x6

Step 3: so the first part that works is n(n+2) but this only gets us close, not exact

Step4: for n=3 which is 16 is n(n+2)+1; for n=4 it is 26 which is n(n+2)+2

Step 5: so now we can try n(n+2)+(n-2). We test this for n=5 which is 38. 5(5+2)+(5-25) = 38. Test again for n=6 which is 52. 6(6+2)+(6-2) = 52...so all good.

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Jason Huang

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1y ago

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