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because the ratio of one side of a triangle to the hypotenuse can never be more that one.

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Q: Why can't the sine of the theta equal 2?
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Sine squared in terms of cosine?

(1 - cos(2x))/2, where x is the variable. And/Or, 1 - cos(x)^2, where x is the variable.


Prove that a constant vector always has a perpendicular derivative?

A dot A = A2 do a derivative of both sides derivative (A) dot A + A dot derivative(A) =0 2(derivative (A) dot A)=0 (derivative (A) dot A)=0 A * derivative (A) * cos (theta) =0 => theta =90 A and derivative (A) are perpendicular


Show that sin x equals cos x for some angle t between 0 and 90?

sin(x) = cos(x)sin(x)/cos(x) = tan(x) = 1x = arctan(1) = 45 degreessin(45)=cos(45) = Sqrt(2)/2 Answer: By observation. Since Sine = Opposite over hypotenuse and Cosine = Adjacent over hypotenuse. Any right angle triangle where the opposite and adjacent sides are the same length will have Sine equal to Cosine. This only happens with an isosceles triangle (two sides are equal in length). When one angle is 90o the other two are 45o.


How do you use double integrals to find the surface area of two intersecting cylinders of radius 1?

To find the area of one cylinder you integrate over dh and dt (theta) like this: r.dt.dh with dt from 0 to 2pi radians. The intersection changes the limits of theta. Assuming that the center of the second cylinder is exactly R from the other cylinder then theta goes from 0 to 2pi*2/3. The 2/3 is because you have removed 120 degrees. However you now have two cylinders so you need to double it to: 2*2pi*2/3 which when factor in the height H and radius R gives you 8pi/3*R*H


What is sine squared?

Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).

Related questions

What is cosine 2 theta when sine theta equals .28?

If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432


What does negative sine squared plus cosine squared equal?

To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)


Sine 2 theta sine4 theta 0?

That is not a question.


How do you find the sine of an angle?

sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)


Why does Sine Theta equal Sine 180 minus Theta?

When you subtract theta from 180 ( if theta is between 90 degrees and 180 degrees) you will get the reference angle of theta; the results of sine theta and sine of its reference angle will be the same and only the sign will be different depends on which quadrant the angle is located. Ex. 150 degrees' reference angle will be 30 degrees (180-150) sin150=1/2 (2nd quadrant); sin30=1/2 (1st quadrant) 1st quadrant: all trig functions are positive 2nd: sine and csc are positive 3rd: tangent and cot are positive 4th: cosine and secant are positive


What are the domains of sine cosine and tangent?

The domain of a function is the set of values of the independent variable for which the function is valid. In practice, this is the allowable values of X or, in this case, theta. The sine and cosine functions have a domain of all numbers from negative infinity to positive infinity. The tangent function, however, is sine(theta) / cosine(theta). Cosine(theta) has value of zero at theta equal to pi / 2, 3pi/2, 5pi/2, ... in the positive direction, and -pi/2, -3pi/2, -5pi/2, ... As a result, tangent(theta) is undefined at these values, so the domain of tangent is all numbers from negative infinity to positive infinity except all numbers n pi/2 where n is odd.


What does 2sin squared theta equal and why?

It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!


Why value of sin theata is in between 1 and -1?

2


What is the value of theta if 4sin theta is equal to 2?

4 sin(theta) = 2 => sin(theta) = 2/4 = 0.5. Therefore theta = 30 + k*360 degrees or 150 + k*360 degrees where k is any integer.


What is sec theta if tan theta equals 2 with theta in quadrant 3?

If tan theta equals 2, then the sides of the triangle could be -2, -1, and square root of 5 (I used the Pythagorean Theorem to get this). From this, sec theta is negative square root of 5. It is negative because theta is in the third quadrant, where cosine, secant, sine, and cosecant are all negative.


Why tan theta sin theta divided by cos theta?

The answer depends on how the ratios are defined. In some cases tan is DEFINED as the ratio of sine and cosine rather than from the angle in a right angled triangle.If the trig ratios were defined in terms of a right angled triangle, thensine is the ratio of the opposite side to the hypotenuse,cosine is the ratio of the adjacent side to the hypotenuse,and tangent is the ratio of the opposite side to the adjacent side.It is then easy to see that sin/cos = (opp/hyp)/(adj/hyp) = opp/adj = tan.If sine and cosine are defined as infinite sums for angles measured in radians, iesin(x) = x - x^3/3! + x^5/5! - x^7/7! + ...andcos = 1 - x^2/2! + x^4/4! - x^6/6! + ...then it is less easy to see tan = sin/cos.


Is the light that passes threw an oblique angle into a material of lower optical density less than the angle of refelction?

According to Snell's Law n1*sine(theta 1)=n2*sine(theta 2) where n1 and n2 is the index of refraction of two substances respectively, and theta 1 and theta 2 is The angle of reflection or refraction angle measured from the optic normal (a line perpendicular to the contact surface of the two materials) respectively. The light that is reflected will do so at the angle theta 1. The portion of the ray that is refracted will be at the angle theta 2. In your question, the index of refraction (a numerical value proportional to the optic density) of the second material is lower (n1>n2). Therefore in order to satisfy Snell's Law the sine(theta 2) must be a higher number corresponding to some greater angle.