It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
42 and 84
They are 24 and 48.
The first 5 multiples of 2 are: 0,2,4,5,8 I'm not sure what you mean by positive but there they are! I hope this helped you. ~Starcoach25 (;
A normal die has two multiples of 3: 3 and 6.
90
5 + 10+15+20=50 ans
It is: 6+12+18 = 36
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
2
Well, isn't that a happy little question! To find the sum of the first 6 multiples of 9, you simply add them all together. So, 9 + 18 + 27 + 36 + 45 + 54 equals 189. Just like painting a beautiful landscape, math can be a peaceful and rewarding experience.
(1 x 8) + (2 x 8) = (1 + 2) x 8 = 3 x 8 = 24
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.