The first ten are: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60 . . .
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
42 and 84
They are 24 and 48.
The first 5 multiples of 2 are: 0,2,4,5,8 I'm not sure what you mean by positive but there they are! I hope this helped you. ~Starcoach25 (;
A normal die has two multiples of 3: 3 and 6.
90
5 + 10+15+20=50 ans
It is: 6+12+18 = 36
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
2
(1 x 8) + (2 x 8) = (1 + 2) x 8 = 3 x 8 = 24
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
Why, that's just 6 times the sum of the numbers from 1 to 50 !The sum of the numbers from 1 to 50 is:1 + 50 = 512 + 49 = 513 + 48 = 514 + 47 = 515 + 46 = 51...etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.