0
Still curious? Ask our experts.
Chat with our AI personalities
Ezra
Coach
ProfessorAdd your answer:
Earn +20 pts
The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
Find the distance between the points -2 -10 and -8 -2?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
What is the diagonal measurement of 8 ft by 12 ft?
Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
What is the perimeter of a rectangle 8 meters x 3 meters?
A rectangle 8 metres x 3 metres has a perimeter (distance around) of 22 metres. It has an AREA of 24 square metres.
What is the diagonal measurement of an 8 ft square?
The diagonal measurement of an 8 ft square is: 11.31 feet.
