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The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
Find the distance between the points -2 -10 and -8 -2?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
What is the diagonal measurement of 8 ft by 12 ft?
Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
What is the perimeter of a rectangle 8 meters x 3 meters?
A rectangle 8 metres x 3 metres has a perimeter (distance around) of 22 metres. It has an AREA of 24 square metres.
What is the diagonal dimension of an 8 foot by 8 foot square?
The diagonal dimension is 11.31 feet.
What is the length of a diagonal of a rectangle with a length of 8 meters and width of 6 meters?
Diagonal = 10 meters.
What is the diagonal length of a rectangle with the sides of 10 and 8?
About 12.7. (I got it from using the pythagreon theyrom.)
What is the perimeter of a rectangle with 8 inches on the side an 10 inches in a diagonal?
By using Pythagoras it is: 6+8+6+8 = 28 inches
A rectangle has a diagonal of 10 and a length of 8. what is its width?
Using Pythagoras' theorem its width is 6 units in length.
A rectangle is 15ft by 8 ft what is the length of a diagonal of a rectangle?
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
What is the diagonal measurement of an 8' X 16' rectangle?
17.8885'
A rectangle has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width What is the width of the rectangle in centimeters?
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
What is the perimeter of a rectangle with a side that is 8 feet long and a diagonal that is 10 feet long?
The diagonal is 10 feet. The one side is 8 feet and the other side is 6 feet (by Pythagoras 82 + 62 = 102)). The perimeter is thus 28 feet.
What is perimeter of a rectangle with a side of 8 and diagonal of 10?
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
What is the diagonal measurement for a square 10' x 16'?
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
What is diagonal of 10 by 8 ft square?
If you mean a rectangle then its diagonal using Pythagoras; theorem is 2 times the square root of 41 or about 12.806 feet rounded to 3 decimal places.
