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D = sqrt(8^2 + 10^2) = sqrt(164) = 12.81 units, rounded to 2 decimal places.
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The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
What is the diagonal measurement of 8 ft by 12 ft?
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
Find the distance between the points -2 -10 and -8 -2?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
What is the perimeter of a rectangle 8 meters x 3 meters?
A rectangle 8 metres x 3 metres has a perimeter (distance around) of 22 metres. It has an AREA of 24 square metres.
What is the diagonal dimension of an 8 foot by 8 foot square?
The diagonal dimension is 11.31 feet.
What is the length of a diagonal of a rectangle with a length of 8 meters and width of 6 meters?
Diagonal = 10 meters.
What is the diagonal length of a rectangle with the sides of 10 and 8?
About 12.7. (I got it from using the pythagreon theyrom.)
What is the perimeter of a rectangle with 8 inches on the side an 10 inches in a diagonal?
By using Pythagoras it is: 6+8+6+8 = 28 inches
A rectangle has a diagonal of 10 and a length of 8. what is its width?
Using Pythagoras' theorem its width is 6 units in length.
A rectangle is 15ft by 8 ft what is the length of a diagonal of a rectangle?
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
What is the diagonal measurement of an 8' X 16' rectangle?
17.8885'
A rectangle has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width What is the width of the rectangle in centimeters?
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
What is the perimeter of a rectangle with a side that is 8 feet long and a diagonal that is 10 feet long?
The diagonal is 10 feet. The one side is 8 feet and the other side is 6 feet (by Pythagoras 82 + 62 = 102)). The perimeter is thus 28 feet.
What is the diagonal of the rectangle has length 6 and width 8?
The diagonal = the square root of (6 squared + 8 squared) 6 squared+8squared = 100 the square root of 100 = 10 so the length of the diagonal is 10. The above used Pythagoras' theorem which says the square on the diagonal is equal to the sum of the squares on the other two sides.
What is perimeter of a rectangle with a side of 8 and diagonal of 10?
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
What is the diagonal measurement for a square 10' x 16'?
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
