Sin(Theta) = -0.0138
Then
Theta = Sin^(-1) ( -0.0138)
Theta = -0.7909 degrees.
NB On your calcultor look for 'Sin^-1' button, sp,eti,es knowmn as 'ArcSin'.
sin(theta) = 15/17, cosec(theta) = 17/15 cos(theta) = -8/17, sec(theta) = -17/8 cotan(theta) = -8/15 theta = 2.0608 radians.
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
Sin theta of 30 degrees is1/2
(/) = theta sin 2(/) = 2sin(/)cos(/)
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
theta = arcsin(0.0138) is the principal value.
Theta equals 0 or pi.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
0.75
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
sin(0)=0 and sin(very large number) is approximately equal to that same very large number.
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
If sin2(theta) = 0, then theta is N pi, N being any integer
It will be a circle.
2 sin (Θ) + 1 = 0sin (Θ) = -1/2Θ = 210°Θ = 330°
you have to do the arcsin which is sin-1 on your calculator. i have not met anyone in my life who can do sin or arcsin in their head. not even my college teachers. your theta is equal to 20degrees