Sorry, but it is impossible to solve this equation by itself. Since you have two unknowns, you need two equation.
y = 2 (4X2=8) +9 = 17
4x2-y2 = (2x-y)(2x+y)
y=4x2+3x+8
First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2
y = -4x2 + 1 Range = {y:y=<1, y is an element of the reals}
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y > -8
Their noses are both at the origin, and they both open upward, but y=4x2 is a much skinnier parabola.
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Assuming the first function is y = 4x2 + 1, and the second y = 4x2 then the first graph is 1 unit higher than the second.
No. [ y = 4x2 ] is a quadratic equation.
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