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How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
The sum of an integer and twice the next consecutive integer is 29. What are the integers?
9 and 10 9 + 2(10) = 29
Find three consecutive odd integers such that the sum of the first integer twice the second integer and three times the third is 70?
9, 11, and 139 + 2(11) + 3(13) = 9 + 22 + 39 = 70
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
The sum of an integer and twice the next consecutive integer is 29. What are the integers?
9 and 10 9 + 2(10) = 29
Find three consecutive odd integers such that the sum of the first integer twice the second integer and three times the third is 70?
9, 11, and 139 + 2(11) + 3(13) = 9 + 22 + 39 = 70
How would you find 3 consecutive integers such that twice the third is 15 more than the first?
Let's denote the first integer as x. The next two consecutive integers would be x+1 and x+2. According to the given condition, twice the third integer (2(x+2)) is equal to 15 more than the first integer (x+15). Setting up the equation: 2(x+2) = x + 15. Solving this equation will give you the first integer, which you can then use to find the consecutive integers.
If the largest of three consecutive even integers is multiplied by three the product is 2 less than twice the sum of the first two integers find the integers?
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?
Let's represent the three consecutive odd integers as ( 2n-1 ), ( 2n+1 ), and ( 2n+3 ), where ( n ) is an integer. According to the given information, twice the smallest integer ( 2(2n-1) ) is equal to seven more than the largest integer ( 2n+3 ). Setting up the equation, we have ( 4n-2 = 2n+3+7 ). Solving this equation gives us ( n = 6 ). Therefore, the three consecutive odd integers are 11, 13, and 15.
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
If sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest integer?
Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.
What are the two positive integers that have a product of 98 where one integer is twice the other?
The integers are 14 and 7.
The sum of two integers is 51. The larger integer is 3 more than twice the smaller integer. Find the two integers?
no one wants to know the answer. its freaking math
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
